Read filename in a directory
April 16th, 2007
<?
$dir = “./data/”;
$dfile = opendir($dir) or die(’error’);
while (($f = readdir($dfile)) !== false)
{
if (is_file($dir.$f))
{
echo $f . “<BR>”;
}
}
?>
Where am I?
You’re currently at “Read filename in a directory,” an entry on Talk Only by admin on Apr 16 2007 @ 5:25 pm
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